九点连线解锁，把密码忘了，有什么方法解开

假设9个点分别为0 1 23 4 56 7 80, 2, 6, 8开始是等价的1, 3, 5, 7开始是等价的所以只考虑0, 1, 4开始的情况，共3*8!=120960种通过程序计算，符合题主要求的交点个数为0-30的情况共有如下数量：[9338, 19264, 24614, 24258, 18856, 11916, 6356, 3802, 1606, 650, 216, 54, 30, 0, 0, 0, 0, 0, 0, 0, 0]这些加起来等于120960。可以看出最多交点确实是12，有30种（其中有部分等价的）：[0, 5, 6, 1, 8, 3, 2, 7, 4][0, 5, 7, 2, 3, 8, 1, 6, 4][0, 7, 2, 3, 8, 1, 6, 5, 4][0, 7, 5, 6, 1, 8, 3, 2, 4][1, 6, 5, 0, 7, 2, 3, 8, 4][1, 8, 3, 2, 7, 0, 5, 6, 4][4, 1, 6, 5, 0, 7, 2, 3, 8][4, 1, 8, 3, 2, 7, 0, 5, 6][4, 2, 3, 8, 1, 6, 5, 7, 0][4, 2, 3, 8, 1, 6, 5, 0, 7][4, 2, 7, 0, 5, 6, 1, 3, 8][4, 2, 7, 0, 5, 6, 1, 8, 3][4, 3, 2, 7, 0, 5, 6, 1, 8][4, 3, 8, 1, 6, 5, 0, 7, 2][4, 0, 5, 6, 1, 8, 3, 7, 2][4, 0, 5, 6, 1, 8, 3, 2, 7][4, 0, 7, 2, 3, 8, 1, 6, 5][4, 0, 7, 2, 3, 8, 1, 5, 6][4, 5, 0, 7, 2, 3, 8, 1, 6][4, 5, 6, 1, 8, 3, 2, 7, 0][4, 6, 5, 0, 7, 2, 3, 1, 8][4, 6, 5, 0, 7, 2, 3, 8, 1][4, 6, 1, 8, 3, 2, 7, 5, 0][4, 6, 1, 8, 3, 2, 7, 0, 5][4, 7, 2, 3, 8, 1, 6, 5, 0][4, 7, 0, 5, 6, 1, 8, 3, 2][4, 8, 3, 2, 7, 0, 5, 6, 1][4, 8, 3, 2, 7, 0, 5, 1, 6][4, 8, 1, 6, 5, 0, 7, 3, 2][4, 8, 1, 6, 5, 0, 7, 2, 3]